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Engineer Tools

Thermal Expansion Calculator

Formula: ΔL = L₀ × α × ΔT (α in ppm/°C, i.e. 10⁻⁶/°C)

mm
°C
Enter L₀, material CTE, and ΔT to calculate the expansion.

Common Material CTEs

Materialα(ppm/°C)Notes
Steel11.7
Aluminum Alloy23.1Highest, lightweight structures
Copper17Wire, heat sinks
Silicon (Si)2.6Semiconductor substrate
Stainless Steel 30417.2General-purpose SS
Invar Alloy1.2Ultra-low expansion, precision instruments
Use Case

A precision aluminum fixture is designed at room temperature (25°C) but used in a heat-treatment furnace at 120°C. The engineer must calculate the fixture's thermal expansion to confirm part locating accuracy stays within tolerance at high temperature and avoid thermal distortion causing machining errors.

Example

Aluminum alloy (α = 23.1 × 10⁻⁶/°C), fixture original length L₀ = 500 mm / Working ΔT = 120 - 25 = 95°C / Expansion: ΔL = L₀ × α × ΔT = 500 × 23.1×10⁻⁶ × 95 = 1.097 mm / With a locating tolerance of ±0.5 mm, 1.097 mm exceeds tolerance — compensation is required / Option: switch to Invar (α ≈ 1.2×10⁻⁶/°C): ΔL = 500 × 1.2×10⁻⁶ × 95 = 0.057 mm (within tolerance)

Further reading: Thermal expansion calculation and precision machine design
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